algebra
posted by Bill .
The radius of a large pizza is two times plus 3 inches larger than a small pizza. The area of the small pizza is 33 square inches less than the large pizza. What is the radius of the larger pizza?

Call the small pizza radius r and the large pizza radius R.
R = 2r +3
pi R^2 = pi r^2 33
= pi*(4r^2 + 6r + 9)
3r^2 + 6r + (33/pi) +9 = 0
Solve that quadratic for r.
Are you sure the problem did not say
"The area of the small pizza is 33 pi square inches less than the large pizza. " ?
The answer would be easier to write down in that case, because the pi factors would cancel out 
hk,hh