Pre Calc

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x^2+y=9, x-y+3=0. Need to solve using substitution method.

  • Pre Calc -

    from the second ...
    y = x+3
    sub into first
    x^2 +x+3 = 9
    x^2 + x - 6 = 0
    (x+3)(x-2) = 0
    x = -3 or x = 2

    sub both values into y = x+3 to find their corresponding y's

  • Pre Calc -

    Thanks

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