6^2-13x-28
36-13x-28
-13x=-36-28
x=8/13
could you check this problem it had to be done and turn in tonight.
First of all there is no equation at the beginning, how did it suddenly turn into one in the third line?
somebody else posted a very similar question, but it said
solve 6x^2 - 13x - 28 = 0
If that is your question also, then ...
it factors to
(2x-7)(3x+4) = 0
x = 7 or x = -4/3
6x^2-13x-28
36-13x-28=
13x=-36-28
13x=-8/13
Solve equadratic equation by factoring. Is this problem right.
It must turn in tonight. The problem you have it wrong. This is the right one.
Why is noone check this problem for me.
Did you not read my reply??
I solved your question by factoring at 9:54
MY problem does not have a 0 in it.
6x^2-13x-28
Please help with this
Then it cannot possible say or expect you to "solve" it
You can only solve equations, which means that they must contain an "=" sign.
You do not have an equation!!!!
So all you can do is factor it, which I did for you
Sure! Let's check the problem step by step to confirm if your solution is correct.
The problem is:
6^2 - 13x - 28
Step 1: Start by squaring the number 6.
6^2 = 36
Step 2: Substitute the value back into the equation.
36 - 13x - 28
Step 3: Simplify the equation by combining like terms.
36 - 28 = 8
Now the equation becomes:
8 - 13x
Step 4: To solve for x, we need to isolate the variable. Let's move the constant term to the other side of the equation.
8 - 13x = 0
We'll do this by subtracting 8 from both sides of the equation.
Step 5: Subtract 8 from both sides of the equation.
8 - 8 - 13x = 0 - 8
This simplifies to:
-13x = -8
Step 6: To solve for x, divide both sides of the equation by -13.
(-13x) / -13 = (-8) / -13
This reduces to:
x = 8/13
So, your solution of x = 8/13 is correct!