Solve each equadratic equation by factoring.
6^2-13x-28
36-13x-28
-13x=-36+28
x=64/13
check this, correct if wrong
This problem consist of solve each equadratic equation by factoring.
6x^2-13x-28
check the one for me, help to solve this.
6x^2-13x-28
36x-13x-28
36x-13x=49x
x=49/28=1 21/28
please check this for me. It problem solve equadratic equation by factoring.
To solve a quadratic equation by factoring, we need to set the equation equal to zero and then factor the quadratic expression on the left side. Let's go through it step by step for the equation you provided: 6x^2 - 13x - 28.
1. Start by setting the equation equal to zero:
6x^2 - 13x - 28 = 0
2. Look for two numbers that multiply to give the product of the coefficient of x^2 (6) and the constant term (-28) and add up to give the coefficient of x (-13). In this case, the numbers are -7 and 4 because (-7) * 4 = -28 and (-7) + 4 = -3.
3. Rewrite the middle term (-13x) as the sum of the two numbers found in step 2:
6x^2 - 7x + 4x - 28 = 0
4. Group the terms and factor by grouping:
(6x^2 - 7x) + (4x - 28) = 0
x(6x - 7) + 4(6x - 7) = 0
5. Notice that we have a common binomial factor, (6x - 7), which can be factored out:
(x + 4)(6x - 7) = 0
6. Set each factor equal to zero and solve for x:
x + 4 = 0 --> x = -4
6x - 7 = 0 --> 6x = 7 --> x = 7/6
Therefore, the solutions to the equation 6x^2 - 13x - 28 = 0 are x = -4 and x = 7/6.
Now, let's check if x = 64/13 is a solution:
6(64/13)^2 - 13(64/13) - 28 = 0
384/169 - 832/169 - 28 = 0
(-448 - 832) / 169 - 28 = 0
(-1280) / 169 - 28 = 0
-1280/169 - (28 * 13/13) = 0
-1280/169 - 364/13 = 0
-2896/169 = 0 (Not equal to zero)
Therefore, x = 64/13 is not a solution to the equation 6x^2 - 13x - 28 = 0.
Thus, the correct solution to the equation is x = -4 and x = 7/6.