3/2y-3/2y+4=
3(y)-2(y+4)=
3y-2y+8=
y=1/8
check this
Your first statement is not an equation since there is nothing to the right of the = sign. You also need to show parentheses to clarify meaning.
There is no unique solution to what you wrote.
3/2y-3/2y+4
the problem is 3 is over2y then minus 3 over 2y+4 then I work it out. I want someone to check and see if it right.
You cannot solve for y unless there is an "=" sign and something on the other side of it.
You should have written your problem
3/(2y) - 3/(2y+4) = (some constant)
If the constant is zero, then there is no solution for y, because 2y + 4 cannot equal 2y.
If all you are trying to do is rewrite
3/(2y) - 3/(2y+4) with a common denominator, you should have said so.
To check whether y = 1/8 is a solution to the equation 3/2y - 3/2y + 4 = 0, substitute the value of y into the equation and see if both sides are equal.
Substituting y = 1/8 into the equation, we have:
3/2(1/8) - 3/2(1/8) + 4 = 0
To simplify the equation, we perform the arithmetic operations step by step:
(3/2) * (1/8) = 3/16
(3/2) * (1/8) = 3/16
Now, the equation becomes:
3/16 - 3/16 + 4 = 0
Subtracting the fractions gives:
0 + 4 = 0
Since 4 is not equal to 0, we can conclude that y = 1/8 is not a valid solution for the equation 3/2y - 3/2y + 4 = 0.
It is possible that there was an error in the calculations or in the original equation.