Vectors
posted by Marie .
Cross product of vector:
If axb(cross product)=(2,0,1) and bxc= 4,0,4
solve magnitude of axb times magnitude of b x c
a x b xbxc

(2,0,1) = √(4+0+1) = √5
(4,0,4) = √(16+0+16) = √32
so their product is √5√32 = √60 = 2√15
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