A school counselor tests the level of depression in fourth graders in a particular class of 20 students. The counselor wants to know whether the kind of students in this class differs from that of fourth graders in general at her school. On the test, a score of 10 indicates severe depression, while a score of 0 indicates no depression. From reports, she is able to find out about past testing. Fourth graders at her school usually score 5 on the scale, but the variation is not known. Her sample of 20 fiftsh graders has a mean depression score of 4.4.

Suppose the counselor tested the null hypothesis that fourth graders in this class were less depressed than those at the school generally. She figures her t scores to be -.20. What decision should she make regarding the null hypothesis? (Points :1)
Reject it
Fail to reject it
Postpone any decisions until a more conclusive study can be conducted
There is not enough information given to make a decision

With 19 df, you would need t ≥ 2.093 to be significant at P ≤ .05.

What does that tell you?

To determine what decision the school counselor should make regarding the null hypothesis, we need to assess the statistical significance of the t-score. The t-score in this case is -0.20.

To make a decision, the counselor needs to compare the t-score to a critical value or p-value. The critical value or p-value represents the level of significance chosen by the counselor to determine if the results are statistically significant or if they occurred by chance.

However, in the given question, no information is provided about the level of significance or critical values. Without this information, it is not possible to determine the decision regarding the null hypothesis.

Therefore, the answer to this question is: There is not enough information given to make a decision.