algebra 1

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alright i have a few questions if its ok..?

Simplify:
1. -2√(96a^5)

2.√(x+6)^7

3.√18a^5b * √12ab^3

4.√7/8

5. 2√10/6√50

6.1/3√27+27√1/3

7.Solve: √(2x-7) + 3=8

Thanks so much! really appreciate it!

  • algebra 1 -

    I'll do number 7. Bringing the 3 over as a minus 3, we have ã(2x-7)=5, square both sides to get rid of the square root sign and we have 2x-7=25, 2x=32, x=16

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