chemistry
posted by andy .
The solubility product constant (Ksp) for the dissolution of PbSO4 as represented by the chemical equation is 1.7x108.
PbSO4 (s)= Pb2+ (aq) + SO42 (aq)
Calculate the mass (g) of PbSO4 that dissolves in 1100 mL of water.

Pb^+2 = x
SO4^2 = x
Substitute into Ksp and solve.
Then convert M into g/1100 mL. 
What about this question?
Calculate the mass (g) of PbSO4 that will dissolve in 2000 mL of 0.0694 M K2SO4 solution. The equation represents the solubility process.
PbSO4 (s) Pb2+ (aq) + SO42 (aq)
Ksp = 1.7 x 108