what is the answer for (h+3)(h+4)
h^2 + 7h + 12
h(-3-h)
To find the answer for (h+3)(h+4), we can use the distribution property of multiplication over addition. Here are the steps to solve it:
1. Start by multiplying the first terms of each binomial: h * h = h^2.
2. Next, multiply the outer terms: h * 4 = 4h.
3. Then, multiply the inner terms: 3 * h = 3h.
4. Finally, multiply the last terms: 3 * 4 = 12.
Now, let's combine the terms together:
The answer for (h+3)(h+4) is h^2 + 4h + 3h + 12.
Simplifying the expression further:
h^2 + 7h + 12.
So, the final answer is h^2 + 7h + 12.
To find the answer for (h+3)(h+4), we can use the distributive property of multiplication over addition.
Step 1: Multiply the first terms of each binomial: h * h = h^2.
Step 2: Multiply the outer terms of each binomial: h * 4 = 4h.
Step 3: Multiply the inner terms of each binomial: 3 * h = 3h.
Step 4: Multiply the last terms of each binomial: 3 * 4 = 12.
Step 5: Combine the like terms obtained in steps 2 and 3: 4h + 3h = 7h.
Step 6: Put all the terms together to obtain the final answer: h^2 + 7h + 12.
Therefore, the answer for (h+3)(h+4) is h^2 + 7h + 12.