a 500.0 ohm resistor is connected in a series with a capacitor.what must be the capacitance of the capacitor to produce a time constant of 2.00 s
To find the capacitance of the capacitor, we need to use the formula for the time constant of an RC circuit:
τ = R*C
where τ is the time constant, R is the resistance, and C is the capacitance.
Given:
Resistance (R) = 500.0 ohms
Time constant (τ) = 2.00 s
Rearranging the formula, we get:
C = τ / R
Substituting the given values:
C = 2.00 s / 500.0 ohms
C ≈ 0.004 F (Farads)
Therefore, the capacitance of the capacitor must be approximately 0.004 Farads to produce a time constant of 2.00 seconds when connected in series with a 500.0 ohm resistor.