Calculate the mass in grams of 2.74L of CO gas at 33 degrees celcius and 126.0 kPa
I got 3.75 grams
Is this right please
Thanks
My answer is 3.799 g which would round to 3.80. The difference COULD be the conversion from kPa to atm. I used 101.325 and I used 28 for the molar mass CO.
I believe that you are right due to the conversion difference and the fact that none of the other answer are even remotly close !!!
Thanks DR BOB
To calculate the mass of a gas, we need to use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, let's convert the temperature from Celsius to Kelvin. We can do this by adding 273.15 to the temperature in Celsius:
33 degrees Celsius + 273.15 = 306.15 Kelvin
Next, let's convert the volume from liters to milliliters because the ideal gas constant is expressed in milliliters:
2.74 L * 1000 = 2740 mL
Now, let's rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT
The pressure is given as 126 kPa, so we need to convert it to atmospheres (atm) because the ideal gas constant is expressed in atm:
126 kPa * (1 atm / 101.325 kPa) = 1.243 atm
Next, we need to convert the temperature to Kelvin, as discussed earlier (306.15 K).
The ideal gas constant, R, is equal to 0.0821 L * atm / (mol * K).
Plugging in the values to the rearranged equation:
n = (1.243 atm * 2740 mL) / (0.0821 L * atm / (mol * K) * 306.15 K)
Simplifying the calculation:
n = (1.243 * 2740) / (0.0821 * 306.15)
n = 10.9007 mol
Now that we have the number of moles (n), we can calculate the mass using the molar mass of CO, which is approximately 28.01 g/mol.
mass = n * molar mass
mass = 10.9007 mol * 28.01 g/mol
mass = 305.45 grams
Therefore, the correct mass of 2.74 L of CO gas at 33 degrees Celsius and 126.0 kPa is approximately 305.45 grams, which is different from the value you calculated (3.75 grams). Please double-check your calculations to ensure accuracy.