if you burned a marshmallow with a net mass of 0.8g and you heated 49.1 g of water from an initial temperature of 24C to a final temperature of 28C what is the heat energy per gram of marshmallow? (express your answer in J/g)
a. 822 J/g
b. 1027 J/g
c. 4.184 J/g
d. 7210 J/g
q = mass water x specific heat water x (Tinial-Tinitial).
Then q/0.8 = J/g.
the answer I got is 1027 J/g.. right??
To find the heat energy per gram of marshmallow, we need to calculate the heat energy transferred to the water and divide it by the mass of the marshmallow.
First, let's calculate the heat energy transferred to the water using the formula:
q = m * c * ΔT
where:
q = heat energy transferred (in J)
m = mass of water (in g)
c = specific heat capacity of water (4.184 J/g°C)
ΔT = change in temperature (final temperature - initial temperature)
Given:
m = 49.1 g
c = 4.184 J/g°C
ΔT = 28°C - 24°C = 4°C
Substituting the values into the formula, we get:
q = 49.1 g * 4.184 J/g°C * 4°C
q = 821.4576 J
Now, let's find the heat energy per gram of marshmallow:
Heat energy per gram = q / mass of marshmallow
mass of marshmallow = 0.8 g
Heat energy per gram = 821.4576 J / 0.8 g
Heat energy per gram = 1026.822 J/g
Therefore, the heat energy per gram of marshmallow is approximately 1027 J/g. Option b is the correct answer.