What mass of Zn will be dissolved in 10 mL pH=2 HCl solution?

Zn + 2HCl--> ZnCl2 + H2

[H+] = 10^-2 = 0.01M

10 ml = 0.010L
(0.01mol/L)(0.010L) = 0.0001 mole of H+ or HCl
moles of Zn = (0.0001 mol HCl)(1mol Zn/2mol.HCl)= 0.00005 moles Zn
Convert moles of Zn to grams

To determine the mass of Zn that will be dissolved in a given volume of pH=2 HCl solution, we will use the equation given:

Zn + 2HCl → ZnCl2 + H2

First, we need to know the molar concentration (Molarity) of the HCl solution. Let's assume it is given as 1 M (1 mole per liter) because it is not provided in the question.

Next, we need to calculate the number of moles of HCl present in 10 mL of the solution. To do this, we convert 10 mL to liters by dividing by 1000:

10 mL ÷ 1000 = 0.01 L

Since the molarity of the HCl solution is 1 M, the number of moles of HCl can be calculated using the equation:

Moles of solute = Molarity x Volume (in liters)

Moles of HCl = 1 M x 0.01 L = 0.01 moles

According to the balanced equation, 1 mol of Zn reacts with 2 moles of HCl. Therefore, the moles of Zn required for complete reaction can be calculated as:

Moles of Zn = 0.01 moles of HCl ÷ 2 = 0.005 moles

Finally, to determine the mass of Zn, we need to know its molar mass. The molar mass of Zn is 65.38 g/mol.

Mass of Zn = Moles of Zn x Molar mass of Zn
= 0.005 moles x 65.38 g/mol
= 0.327 g

Therefore, approximately 0.327 grams of Zn will be dissolved in 10 mL of pH=2 HCl solution.