How would you balance Na2O plus HOH
Na2O + H2O -> 2NaOH
Put this down in your memory bank.
metal oxide + H2O ==> base.
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To balance the equation Na2O + H2O, which represents the reaction between sodium oxide and water, we need to ensure that the same number of atoms of each element are present on both sides of the equation.
Here's the step-by-step process to balance the equation:
1. Count the number of sodium (Na) atoms on each side:
- There are 2 sodium atoms on the left side (2 Na).
- There is 1 sodium atom on the right side (Na).
2. To balance the sodium atoms, add a coefficient of 2 in front of the NaOH on the right side:
Na2O + 2H2O → 2NaOH
3. Next, count the number of oxygen (O) atoms on each side:
- There are 2 oxygen atoms in the sodium oxide and 2 oxygen atoms in water on the left side.
- There are 2 oxygen atoms in the NaOH on the right side.
4. The oxygen atoms are already balanced, so no additional coefficients are needed for oxygen.
5. Finally, count the number of hydrogen (H) atoms on each side:
- There are 2 hydrogen atoms in water (2 H2O) on the left side.
- There are 2 hydrogen atoms in the NaOH on the right side.
6. The hydrogen atoms are already balanced, so no additional coefficients are needed.
The balanced equation is:
Na2O + 2H2O → 2NaOH