Algebra 2 with trigonometry
posted by T .
A baseball diamond is a square 90 feet on a side. The pitcher's mound is 60.5 feet from home. How far does the pitcher have to run to cover first? (we are using the LAW OF SINES AND COSINES)
I see it as a simple Pythagorean problem
x^2 + 60.5^2 = 90^2
x = 66.6 feet
OOPS, I assumed wrongly that the pitcher was halfway between home and second.
the way you state it results in a a Law of Cosine problem
x^2 = 90^ + 60.5^2 - 2(90)(60.54059.857)cos 45
x = 63.72 feet