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SO3, CaCO3, Ag2S, and Zn(OH)2. Is this right?
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I think that these precipitates have their molar solubility affected by pH changes: BaSO3, CaCO3, Ag2S, Zn(OH)2.
Is this right?
Top answer:
Yes, all of them are more soluble in acid solution (even dilute acid solution).
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Argentite (Ag2S) is one of the common ores of silver. If you would like to get 26.2 moles of silver, how many kilograms of Ag2S
Top answer:
There are 2 mols of Ag in every mol of Ag2S 26.2 mols of Ag is therefore 13.1 mols of Ag2S a mol of
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Argentite (Ag2S) is one of the common ores of silver. If 88.1 grams of sulfur was removed from ore, how many grams of Ag2S were
Top answer:
mm = molar mass 88.1 g S x (mm Ag2S/atomic mass S) = ? g Ag2S
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Argentite (Ag2S) is one of the common ores of silver. If 88.1 grams of sulfur was removed from ore, how many grams of Ag2S were
Top answer:
Ag 2 = 2*107.87 = 215.74 grams / mol of Ag2S S = 32.06 grams / mol of Ag2S so Ag2S = 247.8 grams /
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What is the molar solubility of silver sulfide, Ag2S? (Ksp for Ag2S is 6.0 x 10^51.)
Top answer:
To find the molar solubility of silver sulfide (Ag2S), we can use the solubility product constant
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Given the reaction 2HI (aq) + CaCO3(s) = CaI2(aq)+CO2(g)+H2O(l) What volume of of CO2 can be produced from 255mL of 3.0M HI and
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This is a limiting reagent (LR) problem. You know that because amounts are given for BOTH reactants.
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For the following equilibrium system, which of the changes will form more CaCO3 (more moles CaCO3)?
CO2 + Ca(OH)2=CaCO3 +H2O
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Le Chatelier's Principle says, in simple terms, that a system in equilibrium will try to undo what
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How many milliliters of 0.418 M HCl are needed to react with 52.7 g of CaCO3?
2HCl (aq) + CaCO3 (s) >>> CaCl2 (aq) + CO2 (g) +
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Thanks for showing your work. That makes it easier to find the error. You're ok to the last step. I
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Which of the changes will form more CaCO3 (more moles CaCO3)?
CO2 + Ca(OH)2=CaCO3 +H2O delta H =-113kJ Write and explain if
Top answer:
To determine which changes will result in the formation of more moles of CaCO3, we need to consider
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suppose that you could decompose 0.250 mole of Ag2s into its elements
a.How many moles of silver would you have? how many moles
Top answer:
Ag2S ==> 2Ag^+ + S^-2 0.250 moles Ag2S will give you 2x0.250 moles Ag because the formula tells you
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ou are given the following data.
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