I need to express as an equivalent expression that is a sum of

logarithms.
logt 13ab2
is this right (log+13t+loga+log+b+log+2)

No, it isn't right. Why is there a t right after log? "Log" by itself is not a number. Is the "2" an exponent? If so, write a ^ in front of it.

Did you mean to write log(t^13*a*b^2) ?
That would be 13 log t + log a + 2 log b

To express logt 13ab2 as an equivalent expression that is a sum of logarithms, you can use the properties of logarithms. In this case, you can use the product rule of logarithms, which states that log(xy) = log(x) + log(y).

Here's how you can break down logt 13ab2 into a sum of logarithms:

1. Start with logt 13ab2.
2. Apply the product rule of logarithms to split the expression 13ab2 into individual factors:
logt (13) + logt (a) + logt (b2).
3. Notice that 13 is just a constant, so logt (13) remains as it is.
4. Similarly, a and b2 are variables, so logt (a) and logt (b2) remain as they are.
5. Finally, you can express logt 13ab2 as:
logt (13) + logt (a) + logt (b2).

Therefore, the correct equivalent expression that is a sum of logarithms for logt 13ab2 is logt (13) + logt (a) + logt (b2).