The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams of water?
If it was 1 gram it would be 540 calories, but you have 500 g so how many calories?
540*500=270000
To find out how many calories are required to completely vaporize 500 grams of water, you can use the equation:
Heat energy = mass × latent heat of vaporization
First, let's plug in the values we know:
Mass of water = 500 grams
Latent heat of vaporization for water = 540 calories/gram
Now, we can substitute these values into the equation:
Heat energy = 500 grams × 540 calories/gram
To calculate this, multiply the mass of water (500 grams) by the latent heat of vaporization (540 calories/gram):
Heat energy = 270,000 calories
Therefore, 270,000 calories are required to completely vaporize 500 grams of water.