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A ladder 14 ft long rests against a vertical wall. Let \theta be the angle between the top of the ladder and the wall and let x be the distance from the bottom of the ladder to the wall. If the bottom of the ladder slides away from the wall, how fast does x change with respect to \theta when \theta = \pi / 3?

  • math -

    sinØ = x/14

    cosØ = (1/4)dx/dØ
    dx/dØ = 4cosØ

    so when Ø = π/3
    dx/dØ = 4cosπ/3 = 2

  • OOPS - math -

    somehow my 14 changed to 4,
    (need new specks)

    so all the 4's are 14's
    and last line is
    dx/dØ = 14cos π/3 = 7

  • OOPS#2 - math -

    just realized that drwls had already answered the question correctly,

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