"The probability of getting heads on a biased coin is 1/3. Sammy tosses the coin 3 times. Find the probability of getting two heads and one tail".
I thought that all you have to do is:
It makes sense to me, but it's not right...
Here are the possibilities:
Each one has a probability of (1/3)(1/3)(2/3) = 2/27. For either-or probabilities, add the probabilities of the individual events.
I WOULD PUT IT AS A SIMPLE 1/3