# Math

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"The probability of getting heads on a biased coin is 1/3. Sammy tosses the coin 3 times. Find the probability of getting two heads and one tail".

I thought that all you have to do is:
(1/3)(1/3)(2/3)

It makes sense to me, but it's not right...

• Math -

Here are the possibilities:

HHT
HTH
THH

Each one has a probability of (1/3)(1/3)(2/3) = 2/27. For either-or probabilities, add the probabilities of the individual events.

• Math -

I WOULD PUT IT AS A SIMPLE 1/3

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