an 80 kg physics student is riding the cajun cliffhanger. this ride had a diameter of 8.0m (u:0.06)the ride produces enough centripetal force to suspend a student.

1.what is the force of friction to keep the student suspended?
2.what normal force is required to generate the friction needed to keep the suspended?
3.at what speed does the ride have to spin in order to generate the forces required in the second question?

Suspension sounds like a good idea.

To answer these questions, we need to apply some basic principles of circular motion and forces.

1. To find the force of friction required to keep the student suspended, we first need to determine the centripetal force acting on the student. The centripetal force is given by the formula:

Fc = m * v^2 / r

where Fc is the centripetal force, m is the mass of the student (80 kg), v is the speed of the ride, and r is the radius of the circular path (half of the diameter, so 4.0 m).

Since the ride is producing enough centripetal force to suspend the student, the force of friction must be equal in magnitude and opposite in direction to the centripetal force. So, the force of friction required to keep the student suspended is also Fc.

2. The normal force is the force exerted by a surface perpendicular to the surface. In this case, it is the force exerted by the platform or ride on the student. When the student is suspended, the normal force must be equal in magnitude and opposite in direction to the force of gravity acting on the student.

The formula to calculate the force of gravity is:

Fg = m * g

where Fg is the force of gravity, m is the mass of the student (80 kg), and g is the acceleration due to gravity (9.8 m/s^2).

Therefore, the normal force required to generate the friction needed to keep the student suspended is also Fg.

3. To find the speed at which the ride must spin to generate the forces required in question 2, we can rearrange the formula for centripetal force:

Fc = m * v^2 / r

Solving for v, we get:

v = sqrt(Fc * r / m)

Substituting the values given, we get:

v = sqrt((Fg * r) / m)

So, the speed required for the ride to generate the necessary forces is equal to the square root of (Fg * r) divided by m.

Remember to plug in the values for Fg (m * g), r, and m to calculate the speed accurately.