1. A block of mass m=100kg rests on a level ground. With what force, parallel to the ground, must you push the block so that it is just ready to start sliding? The coefficient of static friction between the block and the ground is 0.40.
Force required = (mass)*g*(mus)
where mus is the static friction coefficient and g is the acceleration of gravity. Use SI units for the force in Newtons
400N
To find the force required to just start sliding the block, we need to consider the force of static friction acting on the block.
The formula for static friction is:
fs = μs * N
Where:
fs is the force of static friction,
μs is the coefficient of static friction, and
N is the normal force acting on the block.
The normal force is the force exerted by the ground on the block and is equal to the weight of the block (mg).
So, N = mg
Plugging in the values:
m = 100 kg (mass of the block)
g = 9.8 m/s² (acceleration due to gravity)
N = 100 kg * 9.8 m/s²
N = 980 N
Now we can calculate the force of static friction:
fs = μs * N
fs = 0.40 * 980 N
fs = 392 N
Therefore, to just start sliding the block, you would need to apply a force parallel to the ground that is equal to or greater than 392 N.