# algebra II-URGENT

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the perimeter of a rectangular yard is 270 feet. If its length is 25 feet greater than its width what are the dimensions of the yard

• algebra II-URGENT -

P=2l+2w
270=2(w+25)+2w
270=2w+50+2w
220=4w
55=w
so

l=w+25
=55+25
=80

Check
P=2l+2w
270=2(80)+2(55)
270=160+110
270=270

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