The perimeter of a rectangular yard is 270 feet. If its length is 25 feet greater than its width, what are the dimensions of the yard?
A yard has a perimeter of 232 feet. If twelve times the length of the yard equals seventeen times the width, what are its dimensions?
To find the dimensions of the yard, we can set up an equation using the given information. Let's say the width of the yard is "w" feet.
According to the problem, the length of the yard is 25 feet greater than its width. So the length would be "w + 25" feet.
The formula for the perimeter of a rectangle is given by: P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
In this case, the perimeter is given as 270 feet, so we can substitute the values into the formula:
270 = 2(w + 25 + w)
Simplifying the equation further:
270 = 2(2w + 25)
Distributing the multiplication:
270 = 4w + 50
Subtracting 50 from both sides:
220 = 4w
Dividing by 4:
w = 55
Now that we have the value of "w" (the width), we can find the length of the yard:
Length = w + 25 = 55 + 25 = 80
So the dimensions of the yard are 55 feet (width) and 80 feet (length).