A cubic box of volume 4.1×10^-2 m^3 is filled with air at atmospheric pressure at 20 degrees C. The box is closed and heated to 181 degrees C. What is the net force on each side of the box?

Use the combined gas law to find the new pressure, then

force on each side= pressure*area of that side.

To find the net force on each side of the box, we first need to calculate the change in pressure inside the box due to the increase in temperature.

We can use the ideal gas law equation to relate pressure, volume, and temperature:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, let's convert the given temperatures to Kelvin.

20 degrees C = 20 + 273.15 = 293.15 K
181 degrees C = 181 + 273.15 = 454.15 K

Since the number of moles and the gas constant remain constant, we can simplify the equation as:

P1V1 / T1 = P2V2 / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We know that the volume of the box (V1) is 4.1 × 10^-2 m^3 and the initial pressure (P1) is atmospheric pressure. Let's assume the final pressure (P2) is the new pressure inside the box.

Now we can rearrange the equation to solve for P2:

P2 = (P1V1T2) / (V2T1)

Substituting the given values:

P2 = (atmospheric pressure * 4.1 × 10^-2 m^3 * 454.15 K) / (4.1 × 10^-2 m^3 * 293.15 K)

P2 = (atmospheric pressure * 454.15 K) / 293.15 K

P2 = atmospheric pressure * (454.15 / 293.15)

Now, once we have the final pressure (P2), we can find the net force on each side of the box.

Since the box is a cube, it has six faces. The net force on each face is equal in magnitude but opposite in direction, which means the sum of the forces on all six faces will cancel each other out.

The force on each face can be calculated using the formula:

Force = Area * Pressure

Since all the sides of a cube have the same area, we can calculate the force on one face and multiply it by 6.

Let's assume the side length of the cube is L.

The area of one face is A = L^2

Now we can find the net force on each side of the cube:

Net Force = 6 * (Area * P2)

Net Force = 6 * (L^2 * P2)

To calculate the net force, we need to know the side length of the cube. If it is provided, substitute the value of L into the equation. If not, provide the value of the side length to get the final answer.