Math

posted by d

slope-interpept form of the line satisfying the specified conditions: through (-15, -49) and perpendicilar to 5x+8y=-48

  1. Reiny

    The slope of the given line is -5/8

    so the slope of our line is +8/5 and the equation starts
    y = (8/5)x + b
    but (-15,-49) is on it, so
    -49 = (8/5)(-15) + b
    -49 = -24 + b
    b = -25

    equation: y = (8/5)x - 25

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