Calculate the amount of heat required to evaporate 27.5g of water at 100.0 degrees Celsius
1.22 x 10^-2 Kj
To calculate the amount of heat required to evaporate a substance, we need to use the formula:
q = m * ΔHv
Where:
q is the heat required (in Joules),
m is the mass of the substance (in grams), and
ΔHv is the heat of vaporization (in J/g).
For water, the heat of vaporization is approximately 40.7 J/g.
Let's substitute the given values into the formula:
m = 27.5g
ΔHv = 40.7 J/g
q = 27.5g * 40.7 J/g
Calculating the value:
q = 1119.25 J
Therefore, approximately 1119.25 Joules of heat is required to evaporate 27.5g of water at 100.0 degrees Celsius.