Chemistry

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A zero-order reaction has a constant rate of 3.20×10^−4 M/s. If after 35.0 seconds the concentration has dropped to 9.00×10^2M , what was the initial concentration?

  • Chemistry -

    [A] = [A]o - kt
    solve for [A]o. You have k, t, and [A].

  • Chemistry -

    9.00 x 10^-2= (-3.20 x 10^-4)(35)+A
    9.00 x 10^-2= (-.0112)+A
    9.00 x 10^-2+.0112=A
    A= .1012

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