Draw the structure for cis-2,3-dibromo-2-hexene.
We can't draw structures on the board; however, this may help.
C-C=C-C-C-C
Start counting from the left. On carbon 2 place a Br atom. On carbon 3 place another Br atom ON THE SAME SIDE (place the Br atoms both on top or both on bottom). That is the cis form. Fill for a valence of 4 on the other carbons with H atoms.
it does get messed up
oh well.
DO your skeleton 6 legs on the second from right to left your right facing computer put double bond
first and last carbon has h3
left carbons 4,5 have h2 and carbon 2, 3 have br facing each other. IF you put them one up and one down you will create trans.
To draw the structure for cis-2,3-dibromo-2-hexene, you need to take the following steps:
1. Start with a straight chain of six carbon atoms, representing the parent chain of the compound.
H H H H H H
| | | | |
-C-C-C-C-C-C-
2. Number the carbon atoms in the chain from one end to the other. In this case, start numbering from the end that is closest to the double bond containing the substituents.
H H H H H H
| | | | | |
2-C-3-C-4-C-5-C-6-C-
3. Place the double bond between the carbon atoms numbered 2 and 3.
H H H H H H
| | | | |
-C=C-3-C-4-C-5-C-6-C-
|
2
4. Add a bromine atom as substituents on carbon atoms 2 and 3. Since it is cis-2,3-dibromo-2-hexene, the bromine atoms should be on the same side of the double bond.
H H Br H H H
| || | | |
-C=C-3-C-4-C-5-C-6-C-
|
2
H H H Br H H
| | || | |
-C=C-3-C-4-C-5-C-6-C-
|
2
5. Finally, add hydrogen atoms to complete the structure, making sure each carbon atom has the correct number of bonds.
H H Br H H H
| || | | |
-C=C-3-C-4-C-5-C-6-C-
| |
H H
H H H Br H H
| | || | |
-C=C-3-C-4-C-5-C-6-C-
| |
H H
And there you have it! The structure for cis-2,3-dibromo-2-hexene.
cis-2,3-dibromo-2-hexene
br
| br
h2 | |
/\ /\\ | /h3
h3 / \/ \\|/
h2