ALGEBRA
posted by DEBBIE .
need help solving
50=3(r+16) 2(r2) and
5(2x10)/2 + 14 = 19

alright. the first one would be easiest if you multiplied out the numbers before the parenthesiss into the numbers inside. so itll look like 50=3r+482r+4.the u can simplify the right side and get 50=r+52. subtract 52 from both sides and your answer is r=2
the second one first you want to subtract 14 from both sides so you get 5(2x10)/2=5. next you want to divide both sides by 5 because it works out very nicely and you get (2x10)/2=1. next you can take out the 2 on the left because 2x10 can also be written as 2(x5) so you would get x5=1. and lastly you add 5 to both sides so x=6