*simplify by combining like terms, if possible. then, remove the GCF and factor fully.

2x^2-21x+36+x^2
=3x^2-21x+36
...i'm not sure what to do after that, could you help and show the steps please

3x^2-21x+36 GCF: 3, so divide the whole thing by 3.

x^2-7x+12
(What two #s add up to -7 and multiplied equal 12? 3 and 4)

[x^2-4x] - [3x+12]
x(x-4) - 3(x-4)
(x-4)(x-3)=0

x-4= 4 x-3= 3 Answer X=3 and 4

To simplify the expression 2x^2 - 21x + 36 + x^2, the first step is to combine like terms by adding or subtracting them. In this case, we have two terms with x^2 as their variable, so we can add them together.

So, 2x^2 + x^2 becomes 3x^2.
The expression becomes: 3x^2 - 21x + 36.

Next, let's look for the greatest common factor (GCF) of the coefficients in the simplified expression. The GCF of 3, -21, and 36 is 3. We can factor out this GCF from each term.

So, 3x^2 can be factored as 3 * x^2, -21x can be factored as -3 * 7 * x, and 36 can be factored as 3 * 2 * 2 * 3.
The expression becomes: 3(x^2 - 7x + 12).

To factor fully, we need to find two numbers that multiply to 12 and add up to -7 (coefficient of the x term). In this case, the numbers are -4 and -3.

So, we can rewrite the expression as: 3(x - 4)(x - 3).

Therefore, after simplifying, removing the GCF, and factoring fully, the expression 2x^2 - 21x + 36 + x^2 becomes 3(x - 4)(x - 3).

I thought it said, factor fully.

You had
3x^2 - 21x + 36 , which is correct
= 3(x^2 - 7x + 12)
= 3(x-4)(x-3)

nothing was said about "solving" the equation, since there was no equation.