Post a New Question

math

posted by .

*simplify by combining like terms, if possible. then, remove the GCF and factor fully.

2x^2-21x+36+x^2
=3x^2-21x+36
...i'm not sure what to do after that, could you help and show the steps please

  • math -

    3x^2-21x+36 GCF: 3, so divide the whole thing by 3.

    x^2-7x+12
    (What two #s add up to -7 and multiplied equal 12? 3 and 4)

    [x^2-4x] - [3x+12]
    x(x-4) - 3(x-4)
    (x-4)(x-3)=0

    x-4= 4 x-3= 3 Answer X=3 and 4

  • math -

    I thought it said, factor fully.

    You had
    3x^2 - 21x + 36 , which is correct
    = 3(x^2 - 7x + 12)
    = 3(x-4)(x-3)

    nothing was said about "solving" the equation, since there was no equation.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Intermediate Algebra

    Am I going in the right track? 8x -1/x + 5x - 3/2x = 16x^2 - 2x/2x^2 + 5x^2 - 3x/2x^2 16x^2 - 2x + 5x^2 - 3x/2x^2 =21x^2 - 5/2x^2 Find the LCD 6/7z- 28, 8/x^2 -4x = 7x(x-4) Simplify 3x^2 - 2x/15x-10 = x/5 Let's start by looking at
  2. Algerbra

    how do you solve 7(3x+4)=8(2x+5)+13 expand the parenthesis...I will do the left side.. 21x + 29= Now, subtract sixteen x from both sides, and subtract 28 from both sides. I will be happy to check your work. 7(3x+4)=8(2x+5)+13 21x + …
  3. inequality expresion

    The cost of a long distant telephone call is $0.36 for first minutes and $0.21 each additional minutes or portion thereof. Write an inequality representing the number of minutes a person could talk with out exceeding $3.00 would this …
  4. algerbra

    7(3x+4)=8(2x+5)+13 how would I start a equation like this would it be 21x+28=16x+40+13 ?
  5. Algebra

    Is this right? 7(3x-2)=70 21x-14=70; 21x-14+14=70+14; 21x=84; x=4
  6. algebra

    factor the following equation: 6x^2 - 21x - 9 i've tried to factor it and can only get answers for 6x^2 - 21x + 9!
  7. math

    Can someone show me the steps necessary to simplify the expression by combining like terms?
  8. Math

    Simplify I came up with 5.5 (15x^5-21x^4+21x^2)/(3x^2 ) not sure if I did this the correct way it just doesn't seem right at all.
  9. Pre Cal

    find the domains of the following functions: a) f(x)=x^20 b) g(x)=1/(x-3) c) h(x)=1/(4x^2=21x-18) d) k(x)=sqrt (4x^2-21x-18) e) p(x)=1/sqrt(4x^2-21x-18)
  10. algebra 2

    I am trying to factor the expression -8y^2+28y-60 but can't get an answer that is correct. Here is an example of how the problem is supposed to be factored. If you have 21x2-77x-28 the first thing you would do is (21x )(x ). Next you …

More Similar Questions

Post a New Question