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The half-life of stronitum-90 is 28 years. How many grams of this nuclide in a 4.00g sample will remain after 112 years?

  • chemistry -

    k = 0.693/t1/2 = 0.693/28 = ??
    Substitute for k in the equation below.

    ln(No/N) = kt
    ln(4.00/N) = k(112)
    Solve for N.

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