consider the experiment of selecting a card from
an ordinary deck of 52 playing cards and determine the probability
of the stated event.
A red card or a card showing a 5 is drawn.
There are 26 red cards and 2 extra fives. Would my answer be 28/52?
yes
Does this mean that we do not count the two red fives as they would already be counted in the reds.
I would assume that you determined the two probabilities separately.
Red cards = 26/52
5 = 4/52
Either-or probability determined by adding the individual probabilities.
Yes, your answer would be correct. To determine the probability of drawing a red card or a card showing a 5, you need to add the number of red cards (26) and the number of cards showing a 5 (2).
So, the total favorable outcomes (red cards or cards showing a 5) would be 26 + 2 = 28.
The total number of possible outcomes is the entire deck of 52 cards.
Therefore, the probability is calculated as:
Probability = Number of favorable outcomes / Number of possible outcomes
Probability = 28 / 52
Simplifying the fraction, the answer is indeed 28/52, which can be further simplified to 7/13.