posted by Bart .
consider the experiment of selecting a card from
an ordinary deck of 52 playing cards and determine the probability
of the stated event.
A red card or a card showing a 5 is drawn.
There are 26 red cards and 2 extra fives. Would my answer be 28/52?
Does this mean that we do not count the two red fives as they would already be counted in the reds.
I would assume that you determined the two probabilities separately.
Red cards = 26/52
5 = 4/52
Either-or probability determined by adding the individual probabilities.