Write a net equation for the reaction between aqueous solutions of HClO4 and NaH2PO4.
see below
To write the net equation for the reaction between aqueous solutions of HClO4 and NaH2PO4, we need to first identify the ions present in each compound.
HClO4 (perchloric acid) dissociates in water to form the perchlorate ion (ClO4-) and a hydrogen ion (H+):
HClO4(aq) → H+(aq) + ClO4-(aq)
NaH2PO4 (sodium dihydrogen phosphate) dissociates in water to form sodium ions (Na+) and dihydrogen phosphate ions (H2PO4-):
NaH2PO4(aq) → Na+(aq) + H2PO4-(aq)
Now, we need to determine the stoichiometric ratio between these ions to form the products.
In this case, the chloride ions (Cl-) from HClO4 will react with the sodium ions (Na+) from NaH2PO4 to form sodium chloride (NaCl):
ClO4-(aq) + Na+(aq) → NaCl(aq)
The remaining ions, hydrogen (H+) and dihydrogen phosphate (H2PO4-), will combine to form water (H2O):
H+(aq) + H2PO4-(aq) → H2O(l)
Combining these two reactions together, we can write the net equation for the reaction between HClO4 and NaH2PO4 as:
HClO4(aq) + NaH2PO4(aq) → NaCl(aq) + H2O(l)
This equation represents the overall reaction that occurs when HClO4 reacts with NaH2PO4 in aqueous solutions.