does the mole ratio in this question affect the answer?
a 2:1 mixture of O3 and O2 is allowed to effuse through a pinhole in a balloon.after a few seconds, the content of the balloon is analyzed. what will be the mole ratio of the gases in the balloon?
Thanks!
yes, of course. See Graham's law of effusion. If the effusion rate is different for each compound, then for each compound the mole ratio will change. In this case, O2 will effuse faster, so the mole ratio will be greater than 2:1, as more O3 remains.
Yes, the mole ratio does affect the answer in this question. The mole ratio refers to the ratio of moles of one substance to moles of another substance in a balanced chemical equation. In this case, the question states that the mixture in the balloon is a 2:1 ratio of O3 to O2. This means that for every 2 moles of O3, there is 1 mole of O2 in the balloon.
So, the mole ratio of gases in the balloon is 2:1, with 2 moles of O3 to 1 mole of O2.
Yes, the mole ratio in this question does affect the answer. The mole ratio refers to the ratio of moles of one substance to moles of another substance in a chemical reaction or mixture.
In this case, you have a 2:1 mixture of O3 (ozone) and O2 (oxygen). This means that for every 2 moles of O3, you have 1 mole of O2. The mole ratio is 2:1.
When the mixture effuses through a pinhole in the balloon, the O3 and O2 gases will separate based on their rates of diffusion (effusion). O3 being heavier, will effuse more slowly than O2.
However, since the mole ratio of O3 to O2 in the initial mixture is 2:1, the proportion of moles of these gases will remain the same even after effusion. So, the mole ratio of the gases in the balloon will also be 2:1.
Therefore, the mole ratio of gases in the balloon will be 2:1, just like the initial mixture.