what is the balanced equation of the titration CH3COOH(aq) + NaOH(aq) → H2O(l) + NaCH3COO(aq)?
It is balanced.
you may find it easier to write acetic acid this way:
HCH3COO that way the H at the left shows as the + ion, and the CH3COO shows as the negative ion.
To find the balanced equation of the titration reaction mentioned, we need to first determine the chemical formulas of each compound involved.
In this reaction, CH3COOH represents acetic acid, NaOH represents sodium hydroxide, H2O represents water, and NaCH3COO represents sodium acetate.
Now, let's break down the reaction into its ions and balance the equation step-by-step:
1. CH3COOH(aq) → CH3COO-(aq) + H+(aq)
Sodium hydroxide (NaOH) dissociates in water to form sodium ions (Na+) and hydroxide ions (OH-).
Acetic acid (CH3COOH) reacts with sodium hydroxide (NaOH) to form sodium acetate (NaCH3COO) and water (H2O).
In the reaction, one molecule of CH3COOH produces one acetate ion (CH3COO-) and one hydrogen ion (H+).
2. NaOH(aq) → Na+(aq) + OH-(aq)
Sodium hydroxide (NaOH) dissociates in water to form sodium ions (Na+) and hydroxide ions (OH-).
3. Combining the two previous reactions, we have:
CH3COOH(aq) + NaOH(aq) → CH3COO-(aq) + H+(aq) + Na+(aq) + OH-(aq)
4. Now, let's cancel out any common ions on both sides of the equation. In this case, Na+ and OH- are present on both sides, so they can be removed:
CH3COOH(aq) + NaOH(aq) → CH3COO-(aq) + H2O(l) + Na+(aq)
Therefore, the balanced equation for the titration reaction CH3COOH(aq) + NaOH(aq) → H2O(l) + NaCH3COO(aq) is:
CH3COOH(aq) + NaOH(aq) → CH3COO-(aq) + H2O(l) + Na+(aq)