find the vertex f(x)=3x^2-6x+8 I have an answer of -1 and 17 I believe that the correct answer is 1,5 is this correct
To find the vertex of the quadratic function f(x) = 3x^2 - 6x + 8, you can use the formula x = -b / (2a), where a and b are the coefficients of the quadratic function in the form ax^2 + bx + c.
In this case, a = 3 and b = -6. Substituting these values into the formula, we get x = -(-6) / (2 * 3), which simplifies to x = 6 / 6, and further simplifies to x = 1.
To find the corresponding y-coordinate of the vertex, substitute the value of x into the original equation:
f(1) = 3(1)^2 - 6(1) + 8
= 3 - 6 + 8
= 5
Therefore, the vertex of the quadratic function f(x) = 3x^2 - 6x + 8 is (1, 5).
It appears that your belief of the correct answer being (1, 5) is indeed correct. The answer (-1, 17) is not the vertex of the given quadratic function.