Sulfuric acid reacts with hydrogen iodide to produce sulfur dioxide, iodine and water.
a) write total ionic equation
b)write net ionic equation
H2SO4 + 2HI ==> SO2 + 2H2O + I2
The above is the balanced molecula equation. Convert this to an ionic equation (strong acids, strong bases, soluble salts are written as the ions. Gases, liquids (H2O for example) insoluble materials are written as the molecule.)
Then cancel ions common to both sides to obain the net ionic equation.
a) To write the total ionic equation for the reaction between sulfuric acid (H2SO4) and hydrogen iodide (HI), we need to consider that both sulfuric acid and hydrogen iodide are strong acids, meaning they will dissociate completely in water.
The balanced chemical equation for the reaction is:
H2SO4(aq) + 2HI(aq) → SO2(g) + I2(s) + 2H2O(l)
To write the total ionic equation, we need to separate all the soluble ionic compounds into their individual ions. Since all the compounds in this reaction are soluble, we'll have:
H+(aq) + HSO4^-(aq) + 2H+(aq) + 2I^-(aq) → SO2(g) + I2(s) + 2H2O(l)
b) To write the net ionic equation, we need to remove the spectator ions. Spectator ions are the ions that appear as both reactants and products and do not participate in the reaction.
In this reaction, H+ and HSO4^- ions appear on both sides of the equation and do not participate in any chemical change. Thus, they can be considered as spectator ions.
The net ionic equation for the reaction between sulfuric acid and hydrogen iodide becomes:
2I^-(aq) → SO2(g) + I2(s) + 2H2O(l)
Here, only the iodide ions (I^-) are involved in the reaction, producing sulfur dioxide (SO2), iodine (I2), and water (H2O).
a) To write the total ionic equation, you need to break down all the reactants and products into their respective ions.
The reactants are sulfuric acid (H2SO4) and hydrogen iodide (HI). Sulfuric acid dissociates into two hydrogen ions (H+) and one sulfate ion (SO4^2-). Hydrogen iodide dissociates into hydrogen ions (H+) and iodide ions (I^-).
The equation can be written as follows:
H2SO4(aq) + 2HI(aq) → SO2(g) + I2(s) + 2H2O(l)
In the total ionic equation, you represent all the ions that are present as separate species.
2H+(aq) + SO4^2-(aq) + 2H+(aq) + 2I^-(aq) → SO2(g) + I2(s) + 2H2O(l)
b) To write the net ionic equation, you eliminate the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are the hydrogen ions (H+) and sulfate ion (SO4^2-), since they appear on both sides of the equation:
2I^-(aq) → I2(s)
So the net ionic equation for the reaction is:
2I^-(aq) → I2(s)
This equation represents the actual chemical change occurring in the reaction, without the presence of spectator ions.