college algebra
posted by Jake .
what is the y value of the vertex f(x)=x^2+6x+5 I have an answer of 4 this is important because I come up with 4 and I believe the answer to this is 4

we could complete the square
f(x)=x^2+6x+5
= x^2 + 6x + 9  9 + 5
= (x+3)^2  4
so the vertex is (3,4), so you were right
shortcut way:
the x of the vertex is b/(2a) = 6/2 = 3
f(3) = 9  15 + 5 = 4