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college algebra

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what is the y value of the vertex f(x)=x^2+6x+5 I have an answer of 4 this is important because I come up with -4 and I believe the answer to this is 4

  • college algebra -

    we could complete the square
    f(x)=x^2+6x+5
    = x^2 + 6x + 9 - 9 + 5
    = (x+3)^2 - 4

    so the vertex is (-3,-4), so you were right

    short-cut way:
    the x of the vertex is -b/(2a) = -6/2 = -3
    f(-3) = 9 - 15 + 5 = -4

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