college algebra

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what is the y value of the vertex f(x)=x^2+6x+5 I have an answer of 4 this is important because I come up with -4 and I believe the answer to this is 4

• college algebra -

we could complete the square
f(x)=x^2+6x+5
= x^2 + 6x + 9 - 9 + 5
= (x+3)^2 - 4

so the vertex is (-3,-4), so you were right

short-cut way:
the x of the vertex is -b/(2a) = -6/2 = -3
f(-3) = 9 - 15 + 5 = -4

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