Math
posted by B.B. .
Did I do this problem right?
Divide.
x^2+4x48/x+8
Here is how I solved this problem:
x(x+4)48/x+8
(x+4)48/8
(x+4)6
x+46
x=2
Is this correct?
Thanks.

Sorry to say this, but looking at that "solution" made me shudder.
the correct way ... assuming you meant:
(x^2+4x48)/(x+8)
Using long algebraic division, one gets
x  4 with a remainder of 16
or you can use synthetic division to arrive at the same answer.
(x^2+4x48)/(x+8) = (x4)  16/(x+8)
study this example
http://www.mathsrevision.net/alevel/pages.php?page=1