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Calculate [Cu^2+] in a 0.15 M CuSO4 solution that also 6.5 M in free NH3.

Cu^2+ + 4NH3 >>>>>> Cu(NH3)4

kf = 1.1 * 10^11.

thx

  • chemistry -

    tell me the fromula for charles law

  • chemistry -

    1.6 x 10^-17

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