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posted by Ted Tuesday, April 20, 2010 at 9:05pm.

How do you find the derivative of: ln(3x^2 + x - 1) I know the derivative of lnx is 1/x

If y = ln(junk) then dy/dx = junk'/junk so y' = (6x+1)/(3x^2 + x - 1)

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