surgery successful 0.91 and continued health 0.85 are the probability of two outcomes for a patient given surgical for a possible condition.what is the probability of positive outcome (surgery successful or continued health). here are the option
a.0.12 b.0.892 c.0.162 d.0.838 e.0.108 f.0.88
To find the probability of a positive outcome (surgery successful or continued health), we need to use the formula for the union of two events. The formula for the union of two events A and B is given by:
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
In this case, event A represents the surgery being successful (P(A) = 0.91) and event B represents the patient's continued health (P(B) = 0.85). The probability of both events happening together (surgery successful and continued health) is not given, so we'll assume that these events are independent and therefore P(A ∩ B) = P(A) * P(B).
Substituting the values into the formula, we get:
P(Surgery successful ∪ Continued health) = P(Surgery successful) + P(Continued health) - P(Surgery successful) * P(Continued health)
= 0.91 + 0.85 - (0.91 * 0.85)
= 0.91 + 0.85 - 0.7735
= 0.9865
Therefore, the probability of a positive outcome (surgery successful or continued health) is approximately 0.9865.
None of the given options match this value exactly. However, the closest option is option d.0.838, which is the closest approximation to 0.9865.