what mass of acetylene, will be produced from the reaction of 90g of calcium carbide, with water inthe following reaction
CaC2+2H2O-C2H2+Ca(OH)2
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To determine the mass of acetylene produced from the reaction of calcium carbide with water, we need to use stoichiometry. The balanced equation for the reaction is:
CaC2 + 2H2O → C2H2 + Ca(OH)2
From the equation, we can see that 1 mole of CaC2 produces 1 mole of C2H2. We also know the molar mass of CaC2 is approximately 64.1 g/mol. In order to calculate the mass of acetylene produced, we need to convert the mass of calcium carbide to moles, then use the mole ratio to determine the moles of acetylene produced, and finally convert moles of acetylene to grams.
Step 1: Calculate the moles of CaC2
Moles = mass / molar mass
Moles of CaC2 = 90g / 64.1 g/mol ≈ 1.404 mol
Step 2: Determine the moles of C2H2
From the balanced equation, the mole ratio between CaC2 and C2H2 is 1:1. Therefore, the moles of C2H2 produced will also be 1.404 mol.
Step 3: Calculate the mass of C2H2
Mass = moles × molar mass
Mass of C2H2 = 1.404 mol × 26.04 g/mol ≈ 36.6 g
Therefore, approximately 36.6 grams of acetylene will be produced from the reaction.
To determine the mass of acetylene produced, we need to use stoichiometry, which involves calculating the amounts of reactants and products based on the balanced chemical equation. In this case, the balanced equation is:
CaC2 + 2H2O → C2H2 + Ca(OH)2
First, we need to find the molar mass of calcium carbide (CaC2) and acetylene (C2H2). The molar mass of CaC2 is 64.10 g/mol, and the molar mass of C2H2 is 26.04 g/mol.
Next, we will convert the given mass of calcium carbide (90g) to moles. To do this, we divide the mass by the molar mass:
moles of CaC2 = 90g / 64.10 g/mol = 1.4036 mol
According to the balanced equation, 1 mole of calcium carbide (CaC2) reacts to produce 1 mole of acetylene (C2H2). Therefore, the moles of acetylene produced will be the same as the moles of calcium carbide:
moles of C2H2 = 1.4036 mol
Finally, we convert the moles of acetylene to grams by multiplying by the molar mass:
mass of C2H2 = moles of C2H2 * molar mass of C2H2
= 1.4036 mol * 26.04 g/mol
= 36.54 g
Therefore, 36.54 grams of acetylene will be produced from the reaction of 90 grams of calcium carbide with water.
Convert 90 g CaC2 to moles. moles = grams/molar mass
Using th coefficients in the balanced equation, convert moles CaC2 to moles C2H2.
Now convert moles C2H2 to grams. g = moles x molar mass.