when water is added to solid calcium carbide, CaC2, acetylene gas,C2H2,and calcium hydroxide,Ca(OH)2, are produced.
how many moles of calcium carbide are needed to completeley react with
5.00 * 10^22 water molecules?
See below.
To find the number of moles of calcium carbide needed to completely react with a given number of water molecules, we need to use the balanced chemical equation for the reaction between water and calcium carbide:
CaC2 + 2H2O -> C2H2 + Ca(OH)2
From the balanced equation, we can see that the stoichiometric ratio between calcium carbide (CaC2) and water (H2O) is 1:2. This means that for every 1 mole of calcium carbide, we need 2 moles of water to completely react with it.
Now, let's calculate the number of moles of water based on the given number of water molecules (5.00 * 10^22).
Avogadro's number tells us that there are 6.022 * 10^23 water molecules in 1 mole of water. Therefore, we can calculate the number of moles of water as follows:
Number of moles of water = (Number of water molecules) / (Avogadro's number)
= (5.00 * 10^22) / (6.022 * 10^23)
= 0.083 moles of water
Now that we know the number of moles of water, we can determine the number of moles of calcium carbide needed by applying the stoichiometric ratio. Since the ratio is 1:2, we multiply the number of moles of water by 0.5 to get:
Number of moles of calcium carbide = (0.083 moles of water) * (0.5)
= 0.042 moles of calcium carbide
Therefore, approximately 0.042 moles of calcium carbide are needed to completely react with 5.00 * 10^22 water molecules.