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Solve the pairs of simultaneous equations by the substitution method.

  • Math -

    (poor method for this particular question, but ...)

    solve the second for x, (I look for the smallest coefficient)

    3x = 5+8y
    x = (5+8y)/3

    sub into the first
    5(5+8y)/3 - 9y = 17
    multiply by 3 to eliminate fractions
    5(5+8y) - 27y = 51
    25 + 40y - 27y = 51
    13y = 26
    y = 2
    then x = (5+16)/3 = 7

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