12th grade

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Solve this quadratic equation b2 - 10b plus 25 equals 0

  • 12th grade algebra -

    b^2 - 10b + 25 = 0

    (b -5)(b - 5) = 0

    Can you work it from there?

  • 12th grade -

    How to solve 2nd degree equations easily:
    Ax^2+Bx+c=0
    x=(-B+/-sqrt(B^2-4AC))/2A

  • 12th grade -

    I don't agree Anonymous.


    To solve 2nd degrees equations (aka find the roots of a trinomial function), you have first to put it to this form :
    ax² + bx + c = 0 (where a, b and c are reals)

    Then you have to calculate its discriminant (its delta) :
    Δ = b² - 4ac

    If Δ < 0, there is no real solution.
    If Δ = 0, there is one solution :
    x = -b/(2a)
    If Δ > 0, there are two solutions :
    x = (-b + sqrt(Δ))/(2a)
    or x = (-b - sqrt(Δ))/(2a)

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