Math
posted by christopher .
Find the total amount in the compound intrest account.
$4000 is compounded annually at a rate of 11% for 3 years. (Round the nearest hundredths as needed)

Sn = P(1+i)^n
Sn = 4000(1.11)^3 = $5,470.52.
posted by christopher .
Find the total amount in the compound intrest account.
$4000 is compounded annually at a rate of 11% for 3 years. (Round the nearest hundredths as needed)
Sn = P(1+i)^n
Sn = 4000(1.11)^3 = $5,470.52.