elemmanarty algebra
posted by Anonymous .
Divide xy to 3rd power 3xy to 2nd power +2x to 2nd power y by xy

Your description is unclear. If I have this right,
(xy^3  3xy^2 + 2x^2y)/xy = y^2  3y + 2x
However, from the way you have it stated, it could be:
([xy]^3  [3xy]^2 + [2x]^2y)/xy = (xy)^2  9xy + 4x
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